Question
Find the area of a triangle with sides that are 9 in 13 in and 18 in
Answers
Answer
Please choose one of the answers below
40 in squared
63 in squared
126 in squared
47 in squared
40 in squared
63 in squared
126 in squared
47 in squared
Answered by
GPT 3.5
To find the area of a triangle with sides of length 9 in, 13 in, and 18 in, we can use Heron's formula:
s = (9 + 13 + 18) / 2 = 20
Area = √(s(s-9)(s-13)(s-18))
Area = √(20(20-9)(20-13)(20-18))
Area = √(20*11*7*2)
Area = √(3080)
Area ≈ 55.49 square inches
Therefore, the area of the triangle is approximately 55.49 square inches.
s = (9 + 13 + 18) / 2 = 20
Area = √(s(s-9)(s-13)(s-18))
Area = √(20(20-9)(20-13)(20-18))
Area = √(20*11*7*2)
Area = √(3080)
Area ≈ 55.49 square inches
Therefore, the area of the triangle is approximately 55.49 square inches.
Answered by
GPT 3.5
The correct answer is not listed in the options provided. The area of the triangle with sides of length 9 in, 13 in, and 18 in is approximately 55.49 square inches, which is not equivalent to any of the options provided.
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