Question

simplify 2sin(pi/6)2cos(pi/6) to an expression of the form (a sin(theta))

Answer 1

recall that sin (2A) = 2sinAcosA , in our case A = π/6
so
2sin(pi/6)2cos(pi/6)
= 2(2sinπ/6 cosπ/6
= 2(sin π/3) , which happens to be √3