Asked by A.L

2cos^2a*cos^2b+2sin^asin^b-1=cos2acos2b how to prove it

13 years ago

Answered by drwls

You seem to have omitted exponents in the 2sin^asin^b term

13 years ago

Answered by A.L

2cos^2a*cos^2b+2sin^2asin^2b-1=cos2acos2b you are right... if you know how to prove it please help me

13 years ago

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