Asked by A.L

2cos^2a*cos^2b+2sin^asin^b-1=cos2acos2b how to prove it

Answers

Answered by drwls
You seem to have omitted exponents in the 2sin^asin^b term
Answered by A.L
2cos^2a*cos^2b+2sin^2asin^2b-1=cos2acos2b you are right... if you know how to prove it please help me
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions