Ask a New Question

Question

2cos^2a*cos^2b+2sin^asin^b-1=cos2acos2b how to prove it
13 years ago

Answers

drwls
You seem to have omitted exponents in the 2sin^asin^b term
13 years ago
A.L
2cos^2a*cos^2b+2sin^2asin^2b-1=cos2acos2b you are right... if you know how to prove it please help me
13 years ago

Related Questions

1-2sin^2(theta/2)=2cos^2(theta/2)-1 how does 2cos^2 x - 2sin^2 x = 2cos2x 2cos^2a*cos^2b+2sin^2asin^2b-1=cos2acos2b 2cos^2a*cos^2b+2sin^2asin^2b-1=cos2acos2b how to prove it,please help me A wave described by y(x,t)=Asin(kx-wt) moves down a string. What is the maximum transverse speed an... 2Sin tita+2Cos tita=1.5.find tita If f(x)= (4cos^4x+2cos^2x+2sin^2x-x^9-1/2cos4x)^(1/9). Find f(f(2)) simplify 2sin(pi/6)2cos(pi/6) to an expression of the form (a sin(theta)) Express 1/2cos&+√3/2sin& in terns of Cos& only 2Sin(t) + 2Cos(t) = 1.5
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use