Asked by Kewal
Prove that
sin(n+1)Asin(n+2)A + cos(n+1)Acos(n+2)A = cosA
sin(n+1)Asin(n+2)A + cos(n+1)Acos(n+2)A = cosA
Answers
Answered by
drwls
Use the same method as my other proof, but let
(n+1)A = x and
(n+2)A = y
y-x = A
sin(n+1)Asin(n+2)A+cos(n+1)Acos(n+2)A
= sinxsiny + cosxcosy
= cos(y-x) = cosA
(n+1)A = x and
(n+2)A = y
y-x = A
sin(n+1)Asin(n+2)A+cos(n+1)Acos(n+2)A
= sinxsiny + cosxcosy
= cos(y-x) = cosA
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