Asked by Francis
12.5g of zinc trioxocarbonate (iv) znco3 were heated very strongly to a constant mass and the residue treated with excess hydrochloric acid HCl, calculate the mass of zinc chloride zncl2 that would be obtained. (zn=65 c=12 o =16 Cl=35.5)l
Answers
Answered by
DrBob222
Please tell me who taught you to name ZnCO3 that name. It is NOT a correct name by any naming method. Did you learn this in class. Reading on your own. How. A correct name is zinc carbonate but there are others sanctioned by IUPAC.
ZnCO3 --> ZnO + CO2
mols ZnCO3 = g/molar mass = 12.5/113.4 = ?
Convert to mols ZnO.
?Moles ZnCO3 x (1 mol ZnO/1 mol ZnCO3) = xx, then
grams ZnO = mols ZnO x molar mass ZnO = yy.
Post your work if you get stuck.
Please let me know about the naming of ZnCO3.
ZnCO3 --> ZnO + CO2
mols ZnCO3 = g/molar mass = 12.5/113.4 = ?
Convert to mols ZnO.
?Moles ZnCO3 x (1 mol ZnO/1 mol ZnCO3) = xx, then
grams ZnO = mols ZnO x molar mass ZnO = yy.
Post your work if you get stuck.
Please let me know about the naming of ZnCO3.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.