Asked by Emmanuel
10.5g of zinc trioxocarbonate(iv), we're heated very strongly to a constant mass and resdiue treated with excess hydrochloric acid. Calculate the mass of zinc chloride that would be obtained
(Zn=16, C=12, O=16, h=1, Cl=35.5)
(Zn=16, C=12, O=16, h=1, Cl=35.5)
Answers
Answered by
DrBob222
The correct IUPAC name for ZnCO3 is zinc carbonate.
...................ZnCO3 + heat ==> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 = g/molar mass = 10.5 g/approx 125 = about 0.084
0.084 mols ZnCO3 will produce 0.085 mols ZnO and that will produce 0.084 mols ZnCl2.
grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2 = ?
Note: I have estimated molar masses and estimated the calculations so you should recalculate all of the above. Post your work if you get stuck.
...................ZnCO3 + heat ==> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 = g/molar mass = 10.5 g/approx 125 = about 0.084
0.084 mols ZnCO3 will produce 0.085 mols ZnO and that will produce 0.084 mols ZnCl2.
grams ZnCl2 = mols ZnCl2 x molar mass ZnCl2 = ?
Note: I have estimated molar masses and estimated the calculations so you should recalculate all of the above. Post your work if you get stuck.
Answered by
Kiisi
I got 7.7g. Is it correct?
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