Question
10.5g of zinc trioxocarbonate(iv) were heated very stronglu to a constant mass and the residue treated with excess Hcl.calculate the mass of zinc chloride
Answers
ZnCO3 ==> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 = grams/molar mass = ?
1 mol ZnCO3 gives 1 mol ZnO
1 mol ZnO produces 1 mol ZnCl2.
grams ZnCl2 = mols ZnCl2 x molar mass ZnCl3.
ZnO + 2HCl ==> ZnCl2 + H2O
mols ZnCO3 = grams/molar mass = ?
1 mol ZnCO3 gives 1 mol ZnO
1 mol ZnO produces 1 mol ZnCl2.
grams ZnCl2 = mols ZnCl2 x molar mass ZnCl3.
Please give me the answer ido not know
ZnCO3+2HCl ==> ZnCl2+ H2O+CO2
1 mole of ZnCO3=1 mole of ZnCl2
1 mole =10.5/125
Therefore, 10.5/125 *136
Mole=mass/molar mass
Mass = molar mass * mole
i.e. m =136 * 0.1
m = 13.6g
1 mole of ZnCO3=1 mole of ZnCl2
1 mole =10.5/125
Therefore, 10.5/125 *136
Mole=mass/molar mass
Mass = molar mass * mole
i.e. m =136 * 0.1
m = 13.6g
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How did you get 136 and 0.1
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How did you get 136 and 0.1,i want to learn
show working step by step please
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How did you get 136
great
What is the molecular formula of zinc trioxocarbonate IV
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