Asked by Peace

10.5g of zinc trioxocarbonate(iv) were heated very stronglu to a constant mass and the residue treated with excess Hcl.calculate the mass of zinc chloride
Answered by DrBob222
ZnCO3 ==> ZnO + CO2

ZnO + 2HCl ==> ZnCl2 + H2O

mols ZnCO3 = grams/molar mass = ?
1 mol ZnCO3 gives 1 mol ZnO

1 mol ZnO produces 1 mol ZnCl2.

grams ZnCl2 = mols ZnCl2 x molar mass ZnCl3.
Answered by Anonymous
Please give me the answer ido not know
Answered by Kmas
ZnCO3+2HCl ==> ZnCl2+ H2O+CO2

1 mole of ZnCO3=1 mole of ZnCl2

1 mole =10.5/125

Therefore, 10.5/125 *136

Mole=mass/molar mass

Mass = molar mass * mole

i.e. m =136 * 0.1

m = 13.6g
Answered by John Paul
Cool answers you have here keep it up
Answered by Cheta
Wow 🤩 this is nice 👍 keep it up
Answered by Richman Bernard
How did you get 136 and 0.1
i want to learn
Answered by Glory
How did you get 136 and 0.1,i want to learn
Answered by peculiar
show working step by step please
Answered by Joel
I hope it's really correct
Answered by Joey heartz
Good job
Answered by Anonymous
How did you get 136
Answered by Anonymous
great
Answered by Anything
What is the molecular formula of zinc trioxocarbonate IV
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