10.5g of zinc trioxocarbonate(iv) were heated very stronglu to a constant mass and the residue treated with excess Hcl.calculate the mass of zinc chloride

ZnCO3 ==> ZnO + CO2

ZnO + 2HCl ==> ZnCl2 + H2O

mols ZnCO3 = grams/molar mass = ?
1 mol ZnCO3 gives 1 mol ZnO

1 mol ZnO produces 1 mol ZnCl2.

grams ZnCl2 = mols ZnCl2 x molar mass ZnCl3.

Please give me the answer ido not know

ZnCO3+2HCl ==> ZnCl2+ H2O+CO2

1 mole of ZnCO3=1 mole of ZnCl2

1 mole =10.5/125

Therefore, 10.5/125 *136

Mole=mass/molar mass

Mass = molar mass * mole

i.e. m =136 * 0.1

m = 13.6g

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How did you get 136 and 0.1

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How did you get 136 and 0.1,i want to learn

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How did you get 136

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What is the molecular formula of zinc trioxocarbonate IV