To calculate the mass of zinc chloride that would be obtained from the reaction, we need to understand the stoichiometry of the reaction between zinc trioxocarbonate (IV) and hydrochloric acid.
The balanced chemical equation for the reaction can be written as follows:
ZnCO3 + 2HCl → ZnCl2 + CO2 + H2O
From the balanced equation, we can see that 1 mole of zinc trioxocarbonate (IV) reacts with 2 moles of hydrochloric acid to produce 1 mole of zinc chloride.
To solve the problem, we need to follow these steps:
Step 1: Convert the given mass of zinc trioxocarbonate (IV) to moles.
To do this, we use the molar mass of ZnCO3, which is calculated by summing the atomic masses of zinc (Zn), carbon (C), and three oxygen (O) atoms.
The molar mass of ZnCO3 = (65.38 g/mol) + (12.01 g/mol) + (3 * 16.00 g/mol) = 125.38 g/mol
We can now compute the number of moles of ZnCO3 using the formula:
moles = mass / molar mass
moles of ZnCO3 = 10.5 g / 125.38 g/mol
Step 2: Use the stoichiometry of the balanced equation to calculate the moles of zinc chloride.
From the balanced equation, we know that the ratio of moles of ZnCO3 to ZnCl2 is 1:1.
moles of ZnCl2 = moles of ZnCO3
Step 3: Convert moles of zinc chloride to mass.
To do this, we need to know the molar mass of ZnCl2, which is calculated by summing the atomic masses of zinc (Zn) and two chlorine (Cl) atoms.
The molar mass of ZnCl2 = (65.38 g/mol) + (2 * (35.45 g/mol)) = 136.23 g/mol
mass of ZnCl2 = moles of ZnCl2 * molar mass of ZnCl2
Now, let's substitute the calculated values into the equation:
mass of ZnCl2 = moles of ZnCO3 * molar mass of ZnCl2
mass of ZnCl2 = (10.5 g / 125.38 g/mol) * 136.23 g/mol
By performing the above calculation, you will find the mass of zinc chloride obtained from the reaction.