Asked by zakwe
A motor vehicle is uniformly retarded from a velocity 54km/h and finally come to a complete halt after 6s. Determine:
The rate at which it slowed down, and
The distance covered during this speed.
The rate at which it slowed down, and
The distance covered during this speed.
Answers
Answered by
oobleck
a = -54km/hr / 6s = -9 km/hr/s
s = vt + 1/2 at^2
= (54km/hr)(6/3600 hr) - 1/2 (9km/hr/s)(6s)(6/3600 hr)
= 54/600 km - 4.5(6)(1/600) km
= 9/200
= 0.045km = 450m
s = vt + 1/2 at^2
= (54km/hr)(6/3600 hr) - 1/2 (9km/hr/s)(6s)(6/3600 hr)
= 54/600 km - 4.5(6)(1/600) km
= 9/200
= 0.045km = 450m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.