Question
A motor vehicle is uniformly retarded from a velocity 54km/h and finally come to a complete halt after 6s. Determine:
The rate at which it slowed down, and
The distance covered during this speed.
The rate at which it slowed down, and
The distance covered during this speed.
Answers
oobleck
a = -54km/hr / 6s = -9 km/hr/s
s = vt + 1/2 at^2
= (54km/hr)(6/3600 hr) - 1/2 (9km/hr/s)(6s)(6/3600 hr)
= 54/600 km - 4.5(6)(1/600) km
= 9/200
= 0.045km = 450m
s = vt + 1/2 at^2
= (54km/hr)(6/3600 hr) - 1/2 (9km/hr/s)(6s)(6/3600 hr)
= 54/600 km - 4.5(6)(1/600) km
= 9/200
= 0.045km = 450m