Asked by Black mamba
a motor car is uniformly retarded and brought to rest from a velocity of 50km/h in 10sec. find its retardation and the distance covered during this period?
Answers
Answered by
oobleck
the acceleration is clearly (-50km/hr)/(10s) = -5 km/hr/s
now, 1 km/hr = 5/18 m/s
so, a = -25/18 m/s^2
now to find the distance,
s = 250/18 t - 25/36 t^2
plug in t=10
now, 1 km/hr = 5/18 m/s
so, a = -25/18 m/s^2
now to find the distance,
s = 250/18 t - 25/36 t^2
plug in t=10
Answered by
henry2,
Vo = 50km/h = 50,000m/3600s = 13.9 m/s.
V = Vo + a*t = 0.
13.9 + a*10 = 0,
a = -1.39 m/s^2.
V^2 = Vo^2 + 2a*d = 0.
13.9^2 + 2*(-1.39)*d = 0,
d = 69.5 m.
V = Vo + a*t = 0.
13.9 + a*10 = 0,
a = -1.39 m/s^2.
V^2 = Vo^2 + 2a*d = 0.
13.9^2 + 2*(-1.39)*d = 0,
d = 69.5 m.
Answered by
Ummukursum
I did,not understand
Answered by
saminu lawal
Saminu
Answered by
christy
No
Answered by
Joyce
It is correct
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