a motor car is uniformly retarded and brought to rest from a velocity of 50km/h in 10sec. find its retardation and the distance covered during this period?

Answer 1

the acceleration is clearly (-50km/hr)/(10s) = -5 km/hr/s
now, 1 km/hr = 5/18 m/s
so, a = -25/18 m/s^2

now to find the distance,
s = 250/18 t - 25/36 t^2
plug in t=10

Answer 2

Vo = 50km/h = 50,000m/3600s = 13.9 m/s.
V = Vo + a*t = 0.
13.9 + a*10 = 0,
a = -1.39 m/s^2.

V^2 = Vo^2 + 2a*d = 0.
13.9^2 + 2*(-1.39)*d = 0,
d = 69.5 m.

Answer 3

I did,not understand

Answer 4

Saminu

Answer 5

No

Answer 6

It is correct