Asked by El-mubaraq mohd

A motor car is uniformly retarded and brought to rest from velocity 36km/hours in 5 second period it is retardation and distance covered during this period
Answered by oobleck
a = -36km/hr / 5s = -7.2 km/hr/s
distance s = vt + 1/2 at^2, and you know t=5
Answered by Dan
Yes
Answered by Mira
Can I see the full explanation.
Answered by Aisha zakari
Yes but i want to solv pls help me solv
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