Asked by Daberechi

solve this simultaneous equation using substitution method: 5a-2b=14
2a+2b=14
Answered by oobleck
the first equation says that 2b = 5a-14
so use that in the second equation to get
2a+(5a-14) = 14
a=4
so 20-2b=14
b=3
Answered by Praise
How did u get a=4
Answered by Praise
Yes
Answered by Praise
I want to make it clear okay it's 5a - 2b = 14 its the 1st equation then the 2nd says 2a + 2b = 14 so how did u get a = 4🤷how did u solve all this and l don't understand it can u plz make it clear
Answered by Kirtana gunesh
5a + 2b =14
Answered by Anonymous
5a -2b=14, 2a+2b=14 SOLN 7a/7=28/7. a=4
Answered by OLUWASOLA IREOLUWA
5a-2b =14---(1)
2a +2b =14---(2)
2b cancel 2b because they are the same figure. so it remains only
5a =14
+
2a =14
=7a =28 divide both side by 7
a=4.
This is the end of a. So use
5a-2b=14 to get b.
5a-2b =14
5*(4)-2b=14
20-2b=14
Collect like terms
20-14=2b
6=2b divide both side by 2
b=3.
A=4
B=3.
This equation has been successfully solved in the simplest way, if you can only follow the steps.

Answered by Chika
Thank you so much
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