the 2nd equation says that x = 4y-1
So, using that in the first equation,
3(4y-1) - 14y = 0
12y-3 - 14y = 0
-2y = 3
y = -3/2
so, x = 4y-1 = -7
Solve the simultaneous equations: 3X−14Y=0 and X−4Y+1=0
3 answers
I don't think your answer is right
Lindo