Asked by Lillian Scott
A mass of 5.4g of aluminum is reacted with excess copper(II) chloride as shown in the reaction in the image. How much copper can be produced by this reaction?
3 CuCl2 + Al ---> 2 AlCl3 + 3 Cu
3 CuCl2 + Al ---> 2 AlCl3 + 3 Cu
Answers
Answered by
anonymous
Mass of copper produced is 19.07g
Answered by
DrBob222
Your equation is not balanced. The correct balanced equation is as follows:
3 CuCl2 + 2Al ---> 2 AlCl3 + 3 Cu
mols Al = grams/atomic mass = 5.4/27 = 0.2
Convert to mols Cu produced this way.
0.2 mols Al x (3 mols Cu/2 mols Al) = 0.2 x 3/2 = 0.3 mols Cu.
Then grams Cu = mols Cu x atomic mass Cu = 0.3 x 63.54 = 19 g Cu to two significant figures.
3 CuCl2 + 2Al ---> 2 AlCl3 + 3 Cu
mols Al = grams/atomic mass = 5.4/27 = 0.2
Convert to mols Cu produced this way.
0.2 mols Al x (3 mols Cu/2 mols Al) = 0.2 x 3/2 = 0.3 mols Cu.
Then grams Cu = mols Cu x atomic mass Cu = 0.3 x 63.54 = 19 g Cu to two significant figures.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.