Question
What mass of aluminum hydroxide will be produced when 0.460 grams of aluminum sulfide react with water? How many grams of hydrogen sulfide are produced, according to the following equaton?
Al2S3 + H20 -------> Al(OH)3 + H2S
Al2S3 + H20 -------> Al(OH)3 + H2S
Answers
First, balance the equation:
Al<sub>2</sub>S<sub>3</sub> + 6H<sub>2</sub>O --> 2Al(OH)<sub>3</sub> + 3H<sub>2</sub>S
Al<sub>2</sub>S<sub>3</sub> = 150g/mol
H<sub>2</sub>S = 34g/mol
.46g of Al<sub>2</sub>S<sub>3</sub> is 0.003 mole
each mole of Al<sub>2</sub>S<sub>3</sub> produces 3 moles of H<sub>2</sub>S, so you'd get
.009moles of H<sub>2</sub>S = 0.313g
Al<sub>2</sub>S<sub>3</sub> + 6H<sub>2</sub>O --> 2Al(OH)<sub>3</sub> + 3H<sub>2</sub>S
Al<sub>2</sub>S<sub>3</sub> = 150g/mol
H<sub>2</sub>S = 34g/mol
.46g of Al<sub>2</sub>S<sub>3</sub> is 0.003 mole
each mole of Al<sub>2</sub>S<sub>3</sub> produces 3 moles of H<sub>2</sub>S, so you'd get
.009moles of H<sub>2</sub>S = 0.313g
http://www.jiskha.com/science/chemistry/stoichiometry.html
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