Asked by john
What mass of aluminum hydroxide will be produced when 0.460 grams of aluminum sulfide react with water? How many grams of hydrogen sulfide are produced, according to the following equaton?
Al2S3 + H20 -------> Al(OH)3 + H2S
Al2S3 + H20 -------> Al(OH)3 + H2S
Answers
Answered by
Steve
First, balance the equation:
Al<sub>2</sub>S<sub>3</sub> + 6H<sub>2</sub>O --> 2Al(OH)<sub>3</sub> + 3H<sub>2</sub>S
Al<sub>2</sub>S<sub>3</sub> = 150g/mol
H<sub>2</sub>S = 34g/mol
.46g of Al<sub>2</sub>S<sub>3</sub> is 0.003 mole
each mole of Al<sub>2</sub>S<sub>3</sub> produces 3 moles of H<sub>2</sub>S, so you'd get
.009moles of H<sub>2</sub>S = 0.313g
Al<sub>2</sub>S<sub>3</sub> + 6H<sub>2</sub>O --> 2Al(OH)<sub>3</sub> + 3H<sub>2</sub>S
Al<sub>2</sub>S<sub>3</sub> = 150g/mol
H<sub>2</sub>S = 34g/mol
.46g of Al<sub>2</sub>S<sub>3</sub> is 0.003 mole
each mole of Al<sub>2</sub>S<sub>3</sub> produces 3 moles of H<sub>2</sub>S, so you'd get
.009moles of H<sub>2</sub>S = 0.313g
Answered by
DrBob222
http://www.jiskha.com/science/chemistry/stoichiometry.html
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.