Asked by Alisha
aluminum hydroxide is decomposed to form aluminum oxide and water. if 2.23 moles of water are formed then how many of aluminum oxide are formed. how many grams of aluminum hydroxide must have been.decomposed?
Answers
Answered by
DrBob222
4Al(OH)3 ==> 2Al2O3 + 6H2O
2.23 mols H2O x (2 mols Al2O3/6 mols H2O) = 2.23 x 2/6 = ? Look at the coefficients. They tell you the answer.
For part b, how many mols Al(OH)3 must you have started with. That's
2.23 mols H2O x (4 mols Al(OH)3/6 mols H2O). Then convert to grams.
g Al(OH)3 = mols x molar mass = ?
2.23 mols H2O x (2 mols Al2O3/6 mols H2O) = 2.23 x 2/6 = ? Look at the coefficients. They tell you the answer.
For part b, how many mols Al(OH)3 must you have started with. That's
2.23 mols H2O x (4 mols Al(OH)3/6 mols H2O). Then convert to grams.
g Al(OH)3 = mols x molar mass = ?
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