Question
A 100 g mass of aluminum at 100 deg C is placed in 100 g of water at 10 deg C. The final temperature of the mixture is 25 deg C. What is the specific heat of the aluminum?
Answers
Anonymous
q1-q2=0
q1=q2
q1=mc1∆t
q2=mc2∆t
Masses are the same so they aren't needed.
∆t=-75 C°, and c1=???? -75 will just be 75.
∆t=15 C°, and c2=4.186 J/g• C°
c1*(75 C)=(15 C)*(4.186 J/g• C°)
75c=62.79
c=62.79/75
c=0.8372 J/g• C°
Someone check my thinking.
q1=q2
q1=mc1∆t
q2=mc2∆t
Masses are the same so they aren't needed.
∆t=-75 C°, and c1=???? -75 will just be 75.
∆t=15 C°, and c2=4.186 J/g• C°
c1*(75 C)=(15 C)*(4.186 J/g• C°)
75c=62.79
c=62.79/75
c=0.8372 J/g• C°
Someone check my thinking.
neil
mahesh sawant