Asked by Henry
The leaf litter decomposition function of gmelina arboreal at time t(week) is given by=250e^-t/3 find the nutrient lose after 3 weeks and 4 days
Answers
Answered by
Adaolowo
What type of function is y=2e^0.2t
Answered by
Kenro
Find the exponential growth function for a population that doubles in size every unit of time with one individual at zero
Answered by
oobleck
for y(t)=250e^-t/3
3 weeks and 4 days = 25 days, so
y(25) = 250e^(-25/3) = 0.06
a population that doubles in size every unit of time with one individual at zero
p(x) = 1*2^x
3 weeks and 4 days = 25 days, so
y(25) = 250e^(-25/3) = 0.06
a population that doubles in size every unit of time with one individual at zero
p(x) = 1*2^x
Answered by
Anonymous
but I think t is in weeks t = 3 4/7 = 3.57
Answered by
mathhelper
You don't state whether y=250e^-t/3 represents the loss or the amount you have.
anyway, letting you figure that out....
after 3 weeks and 4 days t = 25/7 weeks
y = 250 e^(-25/7 / 3) = 250 e^(-25/21) = 76.02
anyway, letting you figure that out....
after 3 weeks and 4 days t = 25/7 weeks
y = 250 e^(-25/7 / 3) = 250 e^(-25/21) = 76.02
Answered by
Adaolowo
What type of function is y=2e^0.2t
Answered by
Anonymous
exponential
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