prob(your stated event) = C(3,2)/C(8,2) = 3/28
btw, breakdown of probabilities:
both females = 3/28 (see above)
both males = C(5,2)/C(8,2) = 10/28
one male, one female = C(5,1)*C(3,1)/C(8,2 = 15/28
note 3/28 + 10/28 + 15/28 = 28/28 = 1
btw, breakdown of probabilities:
both females = 3/28 (see above)
both males = C(5,2)/C(8,2) = 10/28
one male, one female = C(5,1)*C(3,1)/C(8,2 = 15/28
note 3/28 + 10/28 + 15/28 = 28/28 = 1
First, let's find the total number of possible outcomes. We have a litter of 8 puppies, and we are choosing 2 of them. So, we can use the combination formula:
nCr = n! / (r!(n - r)!)
Here, n is the total number of puppies (8) and r is the number of puppies chosen (2). Plugging in the values, we get:
8C2 = 8! / (2!(8 - 2)!) = (8 * 7) / (2 * 1) = 28
So, there are 28 possible outcomes when choosing 2 puppies from a litter of 8.
Now, let's find the number of favorable outcomes. We want to choose 2 female puppies from the litter, and there are 3 females in total. We can use the combination formula again:
3C2 = 3! / (2!(3 - 2)!) = (3 * 2) / (2 * 1) = 3
So, there are 3 favorable outcomes when choosing 2 female puppies from a litter of 3 females.
Finally, we can find the probability of both puppies being female by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Favorable outcomes / Total outcomes
= 3 / 28
Therefore, the probability that both puppies will be female is 3/28 or approximately 0.107.