Asked by Andrew
In a litter of Pitbull puppies, the probability that a puppy with have light eyes is 35%. If there are 12 puppies born in a litter, what is the probability 5 or more of them will have light eyes? Round answer to 3 decimal places.
Answers
Answered by
R_scott
probability 5 or more light eyes = 1 - probability 4 or less dark eyes
L = p(light eyes) = .35 , D = p(dark eyes) = .65
this is a binomial probability ... light or dark
(L + D)^12 = L^12 + 12 L^11 D + 66 L^10 D^2 + 220 L^9 D^3 + 495 L^8 D^4
sum the 1st five terms , and subtract from 1
L = p(light eyes) = .35 , D = p(dark eyes) = .65
this is a binomial probability ... light or dark
(L + D)^12 = L^12 + 12 L^11 D + 66 L^10 D^2 + 220 L^9 D^3 + 495 L^8 D^4
sum the 1st five terms , and subtract from 1
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