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A ball is thrown so that the motion is defined by the equations x= 5t and y= 2+6t-4.9t^2, where x and y are expressed in meters...Asked by che
. A ball is thrown so that the motion is
defined by the equations x = 5t and y = 2 +
6t – 4.9t2
, where x and y are expressed in
meters and t is expressed in seconds.
Determine (a) the velocity at t =1 s, (b) the
horizontal distance the ball travels before
hitting the ground.
defined by the equations x = 5t and y = 2 +
6t – 4.9t2
, where x and y are expressed in
meters and t is expressed in seconds.
Determine (a) the velocity at t =1 s, (b) the
horizontal distance the ball travels before
hitting the ground.
Answers
Answered by
oobleck
(a)dy/dt = 6-9.8t; dx/dt = 5
Now use those to get the components of v at t=1
(b) find t when y(t)=0, then use that in x(t)
Now use those to get the components of v at t=1
(b) find t when y(t)=0, then use that in x(t)
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