Question

A ball is thrown into the air with an upward velocity of 26 feet per
second. Its height, h, in feet after t seconds is given by the function h(t) = –16t^2 + 26t + 5.

a. How long does it take the ball to reach its maximum height?
Round to the nearest hundredth.

b. What is the ball’s maximum height? Round to the nearest
hundredth.


I am stumped on this. If you can help, please show work

Answer 1

don't forget your Algebra I. h(t) is just a quadratic, and the vertex (maximum height) is at t = -b/2a = 26/32 = 13/16

Now use that to find h(13/16)

Answer 2

I have this h(13/16). I can not get the steps of the problem to solve and get the correct answer of 0.81 seconds. The maximum ball's height to the answer 15.56 feet. I need help please.

Answer 3

huh?? !!
13/16 <b>=</b> 0.8125

h(13/16) = -16(13/16)^2 + 26(13/16) + 5 = 249/16 = 15.5625

or,

h(.8125) = -16*.8125^2 + 26*.8125 + 5 = -10.5625+21.125+5 = 15.5625

Too bad you couldn't be bothered to show <u>your</u> work ...