Asked by Jackie
A particle moves in the x-y plane for t > 0 so that x(t) = t2 + 6t and y(t) = e-t. At time t = 1, the particle is moving (20 points)
A) to the left and up
B) to the right and up
C) to the left and down
D) to the right and down
A) to the left and up
B) to the right and up
C) to the left and down
D) to the right and down
Answers
Answered by
mathhelper
You meant:
x(t) = t^2 + 6t and y(t) = e-t
then x'(t) = 2t and y'(t) = -e^t
x'(1) = 2 and y'(1) = -e
x'(1) is positve and y'(1) is negative.
What does not mean?
x(t) = t^2 + 6t and y(t) = e-t
then x'(t) = 2t and y'(t) = -e^t
x'(1) = 2 and y'(1) = -e
x'(1) is positve and y'(1) is negative.
What does not mean?