Asked by Jackie

A particle moves in the x-y plane for t > 0 so that x(t) = t2 + 6t and y(t) = e-t. At time t = 1, the particle is moving (20 points)

A) to the left and up
B) to the right and up
C) to the left and down
D) to the right and down

Answers

Answered by mathhelper
You meant:
x(t) = t^2 + 6t and y(t) = e-t
then x'(t) = 2t and y'(t) = -e^t
x'(1) = 2 and y'(1) = -e

x'(1) is positve and y'(1) is negative.
What does not mean?
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