Asked by Madison
A particle moves along the x axis. Its position is given by the equation x = 2.00 + 3.20t - 3.85 t2 with x in meters and t in seconds. Determine its position at the instant it changes direction. (in m)
Answers
Answered by
Damon
x = 2 + 3.2 t - 3.85 t^2
when is v = 0?
dx/dt = v = 3.2 - 7.7 t
v = 0 when t = 3.2/7.7 = .416 seconds
then
x = 2 + 1.33 - .665 = 2.66
If you do not know calculus, find the vertex of the original equation.
when is v = 0?
dx/dt = v = 3.2 - 7.7 t
v = 0 when t = 3.2/7.7 = .416 seconds
then
x = 2 + 1.33 - .665 = 2.66
If you do not know calculus, find the vertex of the original equation.
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