Asked by Angela
A particle moves along the x-axis so that at any time t≥0, its velocity is given by v(t)=t^2-16t+4 What is the velocity of the particle when its acceleration is zero?
Answers
Answered by
Reiny
since a(t) = 2t - 16
when a(t) = 0
t = 8
v(8) = 64 - 16(8) + 4 = ......
when a(t) = 0
t = 8
v(8) = 64 - 16(8) + 4 = ......
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