Asked by Ben
A diver runs along a horizontal cliff top of a large lake. She makes contact with the water 1.40 s after leaving the cliff and her contact point is 3.2 m horizontally outward from the edge of the cliff.
a. What is her speed as she leaves the cliff?
b. How tall is the cliff?
c. What is her velocity as she makes contact with the water?
a. What is her speed as she leaves the cliff?
b. How tall is the cliff?
c. What is her velocity as she makes contact with the water?
Answers
Answered by
R_scott
a. 3.2 m / 1.40 s
b. 1/2 * 9.8 m/s^2 * (1.40 s)^2
c. v^2 = (horizontal)^2 + (vertical)^2
... a. is horizontal
... vertical is ... 9.8 m/s^2 * 1.40 s
b. 1/2 * 9.8 m/s^2 * (1.40 s)^2
c. v^2 = (horizontal)^2 + (vertical)^2
... a. is horizontal
... vertical is ... 9.8 m/s^2 * 1.40 s
Answered by
Jacob
Hi,
Are you still in business?
I found a few errors on your site.
Would you like me to send over a screenshot of those errors?
Regards
Jacob
(714) 500-7363
Are you still in business?
I found a few errors on your site.
Would you like me to send over a screenshot of those errors?
Regards
Jacob
(714) 500-7363
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.