Asked by Ben

A diver runs along a horizontal cliff top of a large lake. She makes contact with the water 1.40 s after leaving the cliff and her contact point is 3.2 m horizontally outward from the edge of the cliff.
a. What is her speed as she leaves the cliff?
b. How tall is the cliff?
c. What is her velocity as she makes contact with the water?

Answers

Answered by R_scott
a. 3.2 m / 1.40 s

b. 1/2 * 9.8 m/s^2 * (1.40 s)^2

c. v^2 = (horizontal)^2 + (vertical)^2
... a. is horizontal
... vertical is ... 9.8 m/s^2 * 1.40 s
Answered by Jacob
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