Question

A diver achieves a horizontal velocity of 3.76 m/s from a diving platform located 6m above the water. How far from the edge will the diver be when she hits the water?

Xo = 3.76 m/s.

0.5g*t^2 = 6 m.
4.9t^2 = 6
t^2 = 1.22
Tf = 1.11 s.= Fall time.

Dx = Xo*Tf = 3.76m/s * 1.11s. = 4.16 m.

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