Asked by Dave
Sally runs 2.8 m/s. John runs 1.9 m/s. if John has a 30 m head start. How far before Sally catches John?
Answers
Answered by
MathMate
Time to catch up
=difference in distance / difference in speed
=30/(2.8-1.9) seconds
=difference in distance / difference in speed
=30/(2.8-1.9) seconds
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