Question
12. A body of mass 2kg and a Vol of 0.0005m³ is hung from a balance graduated in Newton . What would be the balance read when the body is in air ?
When it is fully immersed in water ?
When it is immersed in paraffin of of density 800kg?
How help me
When it is fully immersed in water ?
When it is immersed in paraffin of of density 800kg?
How help me
Answers
W = weight = m g = 2 * about 10 m/s^2 = 20 Newtons
force up = volume * density * g = 0.0005 * 1000 kg/m^3 * 10 = 5 Newtons
now reads 20 - 5 = 15 N
Now you can do it for density = 800 instead of 1000
force up = volume * density * g = 0.0005 * 1000 kg/m^3 * 10 = 5 Newtons
now reads 20 - 5 = 15 N
Now you can do it for density = 800 instead of 1000
force up = volume * density * g = 0.0005 * 800 kg/m^3 * 15=6Newtons??
force up = volume * density * g = 0.0005 * 800 kg/m^3 * 10= 8 Newtons??
g is about 10, not 15
so now the scale reads 20 - 8 = 12 Newtons
g is about 10, not 15
so now the scale reads 20 - 8 = 12 Newtons
sorry
force up = volume * density * g = 0.0005 * 800 kg/m^3 * 10= 4 Newtons??
g is about 10, not 15
so now the scale reads 20 - 4 = 16 Newtons
force up = volume * density * g = 0.0005 * 800 kg/m^3 * 10= 4 Newtons??
g is about 10, not 15
so now the scale reads 20 - 4 = 16 Newtons
Thank you
Related Questions
A metre rule is found to balance at the 54cm mark when a body of mass 80g is suspended at the 20cm m...
a uniform half metre rule is freely pivoted at the 20 cm mark and its balance horizontaly when a bod...
A metre rule is found to balance at 51mark. When a body of mass 70g is suspended at the 10cm mark. F...
A uniform meter rule on a knife edge at the 60cm Mark has a mass of 70g hung at the 90cm mark x hung...