Asked by MUSA AUDU

if a body of a mass 4kg is acted upon at constant force of 12n at 2sec,calculate the kenetic energy gain by the body.
Answered by MUSA
YES
Answered by CLEEN
162
Answered by DAVID J
S= ut+1/2at =0 x t + 1/2 x 3 x (2)2 =6m :k.e=W= f x s= 12 x6=72j
Answered by Hilda
A=f/m, =12/4 =3ms-^1
A=∆v/t, =3/1=∆v/2 cross multiply.
Ans=6ms-^2
Hence.1/2mv^2
1/2×4×6^2= 72J.
Answered by Tee gold
A body of mass 4kg is acted upon by a constant :force of 12n for 2second, calculate the k. E gained by the body
Answered by Anonymous
S=ut+1/2at=0 xt+1×3×(2)2=6m :k.e=w=f×s=12×6=72j
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