Question

Body A has twice the mass and three times the specific heat of body B. They are supplied with equal amounts of heat. Body A experiences a temperature change ΔT. What change in temperature is experienced by body B?

Question 2 options:
A) ΔT

B) 3ΔT/2

C) 2ΔT/3

D) 6ΔT

E) ΔT/2

Answer 1

heat=mass*specht*deltaT

deltatempB=heat/massb*specificheatB

deltatempB=6heat/massA*specifheatA=6deltTa

Answer 2

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Answer 3

6