Question

1. A
2. A body with a mass of 490kg is pulled along a horizontal plane at a constant velocity.the pulling force is 1.2 kN is making an angle of 20degrees with the plane.

A.determine the coefficient of friction

3.a force of 318.123N accelerates a car at 3m/s^2 from rest for 10seconds

Calculate the following

A. Mass of the car
B.momentum of the car after 10 seconds
C.velocity of the car after 10seconds

Please help me guys

Answer 1

First question

1.A car moves at a constant velocity up an inclined plane making an angle of 28degrees with the horizontal. The coefficient of friction is 0.387. The force exerted by the engine on the car is 588N.

Calculate the Following

A.weight of the car
B.frictional force acting on the car

Answer 2

2. M*g = 490 * 9.8 = 4802 N. = Wt. of the body.

Fn = Mg-Fap*sin A = 4802-1200*sin20 =
4392 N = Normal force.

Fx-Fs = M*a
1200*Cos20 - Fs = M*0
1128 - Fk = 0
Fk = 1128 N. = Force of kinetic friction

u = Fk/Fn = 1128/4392 = 0.257

3A. F = M*a
F = 318.1 N.
a = 3 n/s^2
M = mass in kg.
Solve for M

C. V = Vo + a*t
Vo = 0
a = 3 m/s^2
t = 10 s.
Solve for V.

B. Momentum = M*V