Asked by Purity

A spring sketch by 6cm when supporting a load of 15N? By how much would it stretch when supporting a load of 5Kg
Answered by Damon
F = k x
15 = k * 6
k = 15/6
5 = (15/6) x
x = 5 * (6/15 ) = 2 cm
Answered by henry2,
Mg = 5*9.8 = 49 N.
15/6 = 49/x
X = 19.6 cm.
Answered by Abusolomon
Please any other way to calculate it
Answered by Shirlen
15000kg-6
Answered by MAHEK
Ratio way
15÷5=6÷x
Cross multiplication
15x=30
x=30÷15
x=2
Answered by Alexandria
can yall explain what ur doing step by step in simpler terms
There are no AI answers yet. The ability to request AI answers is coming soon!