Question

A Spring streches by 6 cm when supporting a load of 15 N.How much would it stretch when supporting a load of 5 kg

Answer 1

15-5=10

Answer 2

x / 6 = (5 g) / 15 ... x = 2 g ... cm

Answer 3

M*g = 5*9.8 = 49 N.
15/6 = 49/x
X =

Answer 4

What load would make the spring extend by 25mm.show working

Answer 5

We are given:

Extension, E = 25 mm = 0.025 m
Load, F = ?

We know that the extension of a spring is directly proportional to the load applied to it. This can be expressed as:

F ∝ E

Or

F = k*E ----(1)

where k is the spring constant.

Now, we can rearrange equation (1) to find k:

k = F/E ----(2)

We can use the given information that the spring extends by 6 cm when a load of 15 N is applied to find k:

k = F/E = 15 N / 0.06 m = 250 N/m

Now, we can use equation (1) to find the load that would make the spring extend by 25 mm:

F = k*E = (250 N/m)*(0.025 m) = 6.25 N

Therefore, a load of 6.25 N would make the spring extend by 25 mm.