Asked by Anonymous
A projectile is launched vertically from the ground at t=0 and its velocity in flight (in m/s) is given by v(t)=20-10t Find the position function, the displacement, and total distance traveled after t seconds for 0≤t≤4, assuming s(0)=0.
Answers
Answered by
oobleck
v(t) = 20-10t
s(t) = 20t-5t^2
the displacement is just s(t)
Since the maximum height of 20 is reached at t=2,
the distance traveled is
s(t) for 0≤t≤2
40-s(t) for 2≤t≤4
since the total distance traveled will be 40 at t=4
s(t) = 20t-5t^2
the displacement is just s(t)
Since the maximum height of 20 is reached at t=2,
the distance traveled is
s(t) for 0≤t≤2
40-s(t) for 2≤t≤4
since the total distance traveled will be 40 at t=4
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