Asked by Teddy
A projectile is launched from ground level at 37.0 m/s at an angle of 30.6 ° above horizontal. Use the launch point as the origin of your coordinate system.
a)How much time elapses before the projectile is at a point 8.9 m above the ground and heading downwards toward the ground?
b)How far downrange (the horizontal distance from the origin) was the projectile when it reached the highest point in its flight?
a)How much time elapses before the projectile is at a point 8.9 m above the ground and heading downwards toward the ground?
b)How far downrange (the horizontal distance from the origin) was the projectile when it reached the highest point in its flight?
Answers
Answered by
bobpursley
hf=hi+vi*t-4.9t^2 vi= 37.0*sin30.6 hf=8.9 hi=0 solve for time t.
YOu get two solutions, take the largest time, it is going down then.
Highest point? Vvertical=0
Vv=0=vi*t-4.9t^2 vi = 37*sin30.6
solve for time t.
then horizontal distce= 37cos30.6*time
YOu get two solutions, take the largest time, it is going down then.
Highest point? Vvertical=0
Vv=0=vi*t-4.9t^2 vi = 37*sin30.6
solve for time t.
then horizontal distce= 37cos30.6*time
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