Ask a New Question

Asked by Anees

A projectile is launched with a speed Vo at an angle 45° with horizontal find ratio of its minimum and maximum K.E ?
4 years ago

Answers

Answered by R_scott
neglecting air resistance ... max K.E. is at launch ... 1/2 * m * Vo^2

min K.E. is at max height
... zero vertical velocity ... horizontal velocity equals ... Vo cos(45º)
... 1/2 * m * (Vo * √2 / 2)^2 = m * Vo^2 / 4
4 years ago

Related Questions

a projectile is launched at 35 degrees above the horizontal with an initial velocity of 120m/s. What... A projectile is being launched from ground level with no air resistance. You want to avoid having it... If a projectile is launched from a platform 30 feet high with an initial velocity of 128 feet per se... A projectile is launched at an angle of 600. What other angle would give the same range for the proj... A projectile is launched with an initial speed of 40m/s at an angle of 25 degrees above the horizont... A projectile is launched at an angle of 60 degrees to the horizontal from 6.5 ft above the ground... A projectile is launched into the air from the ground. The table shows the height of the projectile,... A projectile is launched at 20 m/s. What is the vertical component for velocity at the maximum heig... A projectile is launched from the ground with an upward velocity of 15 m/sec . The maximum height o...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use