Asked by Mike
"A projectile is launched at 517m/s at 50 degrees from the horizontal on top of a building 150m tall. What is the highest point it will reach?"
Need to show all work. Thanks!
Need to show all work. Thanks!
Answers
Answered by
bobpursley
Find the vertical component of velocity
velocityvertical= 517*sin50
Now, the vertical velocity at the top is zero
Vtop^2= Vinitialvertica^2 - 2*g*height
velocityvertical= 517*sin50
Now, the vertical velocity at the top is zero
Vtop^2= Vinitialvertica^2 - 2*g*height
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