Asked by Sam
A projectile is launched with an inital velocity of 30.0m/s at an angle of 60 degrees above the horizontal. How far does it travel. Please show me how to solve this.
Answers
Answered by
PayDay
Draw your triangle
Decide whether to use sin or cos
find value
dh=vht
Solve for dh.
Decide whether to use sin or cos
find value
dh=vht
Solve for dh.
Answered by
bobpursley
Payday: stop answering if you have no idea.
time in air: hf=hi+30sinTheta*t-1/2 g t^2
hi=hf=0
solve for time in air t.
then, hoizontal distance
distance=timeinair*30cosTheta
time in air: hf=hi+30sinTheta*t-1/2 g t^2
hi=hf=0
solve for time in air t.
then, hoizontal distance
distance=timeinair*30cosTheta
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