Question
A projectile is launched at 5.4 m/s with an initial angle of 22 degrees from an initial height of 2.6 meters. Where will it land? How fast, and at what angle will it be going when it hits the ground?
Answers
bobpursley
Vhoriz=5.4*cos22
Vivertical=5.4 sin22
hf=hi+viv*time-4.9t^2
you hf=0,solve for time, it is quadratic.
vvfinal=5.4sin22-gt solve for vfinal
angle when landing:
arctan (vvfinal/vhoriz)
velocityfinal=sqrt(vverfinal^2+vhor^2)
Vivertical=5.4 sin22
hf=hi+viv*time-4.9t^2
you hf=0,solve for time, it is quadratic.
vvfinal=5.4sin22-gt solve for vfinal
angle when landing:
arctan (vvfinal/vhoriz)
velocityfinal=sqrt(vverfinal^2+vhor^2)