Question
A Projectile is launched from the top of a building with an initial velocity of 30m/s at angle of 60° above the horizontal. The magnitude of its velocity at t= 5 s after the launch is
Answers
Henry
Vo = 30m/s[60o].
Xo = 30*Cos60 = 15 m/s.
Yo = 30*sin60 = 26 m/s.
Y = Yo + g*t = 26 - 9.8*5 = -23 m/s.
V^2 = 15^2 + (-23)^2 = 754, V = 27.5 m/s.
Xo = 30*Cos60 = 15 m/s.
Yo = 30*sin60 = 26 m/s.
Y = Yo + g*t = 26 - 9.8*5 = -23 m/s.
V^2 = 15^2 + (-23)^2 = 754, V = 27.5 m/s.