Asked by Emily
A projectile is launched vertically from the surface of the Moon with an initial speed of 1130 m/s. At what altitude is the projectile's speed three-fourths its initial value?
Answers
Answered by
bobpursley
change in PE=change in KE
PE=1/2 mass(1130^2-(3*1130/4)^2 )
Now PE change is Mass*GMm/(altitude+radiusmoon)
so you have to look up the mass of the moon
Notice the mass divides out.
PE=1/2 mass(1130^2-(3*1130/4)^2 )
Now PE change is Mass*GMm/(altitude+radiusmoon)
so you have to look up the mass of the moon
Notice the mass divides out.
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