Asked by panda
1. What is the distance between (5,7) and (-2,-2). Round to the nearest tenth, if necessary.
A. 5.7 units
B. 5.8 units
C. 8.6 units<
D. 11.4 units
Help, please!
A. 5.7 units
B. 5.8 units
C. 8.6 units<
D. 11.4 units
Help, please!
Answers
Answered by
Ms Pi 3.14159265358979323
Not correct... yet
Remember it is the square root of (x2-x1)^2 + (y2 - y1)^2
= square root of (-2 - 5)^2 + (-2 - 7)^2
= square root of (-7)^2 + (-9)^2
= ...
Remember it is the square root of (x2-x1)^2 + (y2 - y1)^2
= square root of (-2 - 5)^2 + (-2 - 7)^2
= square root of (-7)^2 + (-9)^2
= ...
Answered by
oobleck
Just use your distance formula, which is just the Pythagorean Theorem in disguise. The distance is
√((-2-5)^2 + (-2-7)^2) = √(7^2 + 9^2) = √(49+81) = √130
so, not C. How did you arrive at that?
√((-2-5)^2 + (-2-7)^2) = √(7^2 + 9^2) = √(49+81) = √130
so, not C. How did you arrive at that?
Answered by
panda
The square root of 130 would be 11.4, right?
Answered by
Ms Pi 3.14159265358979323
correct : )
Answered by
panda
Thank you!
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