Asked by Ethan
The volume of an ideal gas is increased from 0.92 m3 to 4.07 m3 while maintaining a constant pressure of 1015 Pa (1 Pa = 1 N/m2).
(A) How much work is done by the gas in this expansion?
W=P(V2-V1)
W=1015(4.07-0.92)
W= 3197.25 J
(B) How much work is done by the gas in this expansion?
-No idea what to do here.
(A) How much work is done by the gas in this expansion?
W=P(V2-V1)
W=1015(4.07-0.92)
W= 3197.25 J
(B) How much work is done by the gas in this expansion?
-No idea what to do here.
Answers
Answered by
Damon
You asked the same question twice I think. Typo?