Asked by jenny
An ideal gas has a volume of 3.0 L. If the number of moles of gas and the temperature are doubled, while the pressure remains constant, what is the new volume?
Answers
Answered by
DrBob222
Pick a T (in Kelvin), number of moles, and pressure, calculate V using PV = nRT. Then double N and T and recalculate V.
Answered by
jenny
I just pick any? Don't I have to put 3.0 L in the equation?
Answered by
DrBob222
I thought it would be simpler and you could see how much it increased from one set of data to another.
To use 3L, Use PV = nRT
Set P =1, V = 3, solve for n, use R as 0.08206 and T = 200 (any T will do).
solve for n, the double n, and double T, and solve for V.
The easiest way to do it, logically, is
PV = nRT
use P = 1 and V = 3, then
V = nRT.
3 = nRT. Call n = 1, R is a constant, call T = 1, then 3 = R. Now double n to 2, T to 2 and substitute
V = 2*R*2 = 4V
V was 3 so it is now 12.
Now matter how you set up the numbers, you will always come back to 12 L for the answer.
To use 3L, Use PV = nRT
Set P =1, V = 3, solve for n, use R as 0.08206 and T = 200 (any T will do).
solve for n, the double n, and double T, and solve for V.
The easiest way to do it, logically, is
PV = nRT
use P = 1 and V = 3, then
V = nRT.
3 = nRT. Call n = 1, R is a constant, call T = 1, then 3 = R. Now double n to 2, T to 2 and substitute
V = 2*R*2 = 4V
V was 3 so it is now 12.
Now matter how you set up the numbers, you will always come back to 12 L for the answer.