Asked by Anonymous
The denominator of a fraction in the simplest form is greater than the numerator by 1. If 4 is added to the numerator, and 3 is subtracted from the denominator, then the fraction itself is increased by 2 1/6 . Find the original fraction.
Answers
Answered by
Reiny
current fraction = x/(x+1)
new fraction = (x+4)/(x+1 - 3)
= (x+4)/(x-2)
Their difference is 2 1/6 or 13/6
(x+4)/(x-2) - x/(x+1) = 13/6
multiply each term by 6(x+1)(x-2), the LCD
6(x+1)(x+4) - 6x(x-2) = 13(x+1)(x-2)
6x^2 + 30x + 24 - 6x^2 + 12x = 13x^2 -13x - 26
13x^2 - 55x - 50 = 0
solve using your favourite method of solving quadratics
You will get a whole number and a negative fraction.
I would just stick with the whole number answer.
new fraction = (x+4)/(x+1 - 3)
= (x+4)/(x-2)
Their difference is 2 1/6 or 13/6
(x+4)/(x-2) - x/(x+1) = 13/6
multiply each term by 6(x+1)(x-2), the LCD
6(x+1)(x+4) - 6x(x-2) = 13(x+1)(x-2)
6x^2 + 30x + 24 - 6x^2 + 12x = 13x^2 -13x - 26
13x^2 - 55x - 50 = 0
solve using your favourite method of solving quadratics
You will get a whole number and a negative fraction.
I would just stick with the whole number answer.
Answered by
joe mama
yes that might work but not rly helpful
Answered by
hi
Answer is not right...
Answered by
wrong
wrong
Answered by
RSMCHEATERS
Yo all!
Here is the answer to the question.
1/6
You're all welcome
Here is the answer to the question.
1/6
You're all welcome
Answered by
Anonymous
x/x+1= Original fraction
x+4/x-2=x/x+1+13/6
6x/6x+6+13x+13=x-4/x-2
19x+13/6x+6=x+4/x-2
(cross multiply)
6x^2+20x+24=19x^2-25x-26
55x+50=13x^2
13x^2-55x-50=0
x=5
original fraction=5/6
x+4/x-2=x/x+1+13/6
6x/6x+6+13x+13=x-4/x-2
19x+13/6x+6=x+4/x-2
(cross multiply)
6x^2+20x+24=19x^2-25x-26
55x+50=13x^2
13x^2-55x-50=0
x=5
original fraction=5/6
Answered by
Vel
Anonymous's answer, 5/6 is the right answer, ignore all of the others
Answered by
He he he ha
bro nobdy be writing answers cmon guys
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