Question

a light uniform meter rule PT pivoted at Q the 30cm mark has a block of mass 1.5kg suspended at the 80cm mark. The meter rule is maintained at equilibrium by a string attached at the point R the 50cm mark. What is the tension in the string?
the block is 50 cm from the pivot

the string is 20 cm from the pivot

the tension is ... 1.5 * g * (50 / 20)
WE WANT THE CALCULATION

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