Asked by Moyinoluwa
a light uniform meter rule PT pivoted at Q the 30cm mark has a block of mass 1.5kg suspended at the 80cm mark. The meter rule is maintained at equilibrium by a string attached at the point R the 50cm mark. What is the tension in the string?
Answers
Answered by
R_scott
the block is 50 cm from the pivot
the string is 20 cm from the pivot
the tension is ... 1.5 * g * (50 / 20)
the string is 20 cm from the pivot
the tension is ... 1.5 * g * (50 / 20)
Answered by
OLEBE ROKAS
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