Question

a uniform meter rule is pivoted at 20cm mark .
It is balanced when mass of 100gm on 10cm mark and mass of 50 gm on 30 cm mark are suspended. Find d mass of meter rule
moments around pivot point at 20cm

m(50-20)+50(30-20)=100(20-10)

3m + 50 = 100
no idea
No Idea
By principle of moments.
(10*100)=(50*10)+W*30
So W=(1000-500)/30
=16.67

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