Asked by Winner
A uniform meter rule of weight 0.8n is to be pivoted on a knife edge at the 30cm mark. Where will a force of 4n be placed to balance the meter rule
Answers
Answered by
Anonymous
x is distance left of pivot
4 x = .8 * (50-30)
x = .2 *20 = 4 cm left of 30 = 26 cm mark
4 x = .8 * (50-30)
x = .2 *20 = 4 cm left of 30 = 26 cm mark
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