Question

A uniform meter rule is balance at 30cm mark when of 50grams is hanging from its zero cm mark.calculate the weight of the rule?

Answer 1

m*(50-30) = 50*30 gives MASS, m, in grams (not really weight but is this math or physics?)

Answer 2

the centers of mass of the two segments of the rule are halfway from the balance point to the respective ends

let x = mass of the rule in grams

(50 g * 30 cm) + (.3 x * 15 cm) = .7x * 35 cm

after dividing by 5 ... 300 g-cm + .9x g-cm = 4.9x g-cm

solve for x

Answer 3

Although that should work fine Anonymous, you do not have to split the 100 cm ruler into sections left and right of the balance point. The weight of a rigid body acts as if it were all at the center of mass, no matter what forces are acting on it where.

Answer 4

I want the answer please

Answer 5

I need the workings

Answer 6

physics

Answer 7

clockwise moments=anti-clockwise moments
weight1 multiplied by distance1= weight2 multiplied by distance2
50-30=20
change to newtons
0.5 multiplied by 0.3= 0.2 multiplied by distance2
=0.75 newtons

Answer 8

Answer

Answer 9

0.75 N

Answer 10

0.75N