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A uniform meter rule is balance at 30cm mark when of 50grams is hanging from its zero cm mark.calculate the weight of the rule?
Damon
answered
6 years ago
6 years ago
Anonymous
answered
6 years ago
6 years ago
the centers of mass of the two segments of the rule are halfway from the balance point to the respective ends
let x = mass of the rule in grams
(50 g * 30 cm) + (.3 x * 15 cm) = .7x * 35 cm
after dividing by 5 ... 300 g-cm + .9x g-cm = 4.9x g-cm
solve for x
Damon
answered
6 years ago
6 years ago
Although that should work fine Anonymous, you do not have to split the 100 cm ruler into sections left and right of the balance point. The weight of a rigid body acts as if it were all at the center of mass, no matter what forces are acting on it where.
Melessa
answered
4 years ago
4 years ago
I want the answer please
Franklin
answered
3 years ago
3 years ago
I need the workings
Anonymous
answered
3 years ago
3 years ago
physics
mercy april
answered
3 years ago
3 years ago
clockwise moments=anti-clockwise moments
weight1 multiplied by distance1= weight2 multiplied by distance2
50-30=20
change to newtons
0.5 multiplied by 0.3= 0.2 multiplied by distance2
=0.75 newtons
Anonymous
answered
2 years ago
2 years ago
Answer
Elizabeth Mbithe Kavita
answered
2 years ago
2 years ago
0.75 N
Elizabeth Mbithe Kavita
answered
2 years ago
2 years ago